The formula for voltage on an inductor is stated as
v = L (inductance) x (di / dt)
and current for a capacitor is
i = C (capacitance) x (dv / dt)
But I don't understand what the (dv/dt) part of this equation should be.
In this circuit, if I wanted to know the current on the capacitor at some point in time, how would this be calculated. Would we count the "change in voltage" as going from 0v to the supply voltage in one unit of time? Or would it happen more slowly? How do we know how slowly?
What if there was a switch in this circuit, so there was 0v and then the voltage changed to 1v?