I'm using ActiveBOM in Altium Designer 19. My design has 100k 5% resistors and also has 100k 1% resistors. ActiveBOM gives an informational warning (an "i" with a white circle around it) that the value 100k is a duplicate. I'd like to clear this error.

I'd guess there's a way to suppress this error in Project Options, but I don't want to do that because finding duplicate parts is a good feature.

I could also change the 'Value' field of one of the parts, but that doesn't seem right because they both actually are 100k.

I guess I could change my use of the resistor value field to include the tolerance, but that seems like it might mess up simulation (which I haven't started using yet).

What's the best way?

  • 1
    \$\begingroup\$ This doesn't tell you how to clear the error directly but the cost of 1% vs. 5% resistors (well, 100k resistors) is small, and a quick look shows that the 1% parts can actually be cheaper than the 5% parts. \$\endgroup\$ May 10, 2019 at 13:06
  • \$\begingroup\$ @PeterSmith That's a good point, but I have a similar issue in other places where that substitution doesn't make sense: like a 10k resistor and a 10k thermistor, a 5% resistor and a 0.01% resistor, ... \$\endgroup\$
    – Casey
    May 11, 2019 at 9:30

2 Answers 2


In BOM Checks, click the "gear" icon, set "duplicate value" to "No report"


Some are mentioned above, there are a couple of options here:

  • Suppress reporting of the error, which can hide useful warnings too
  • Combine the parts, where applicable. This is good design (and cost-savings) practice too.
  • Use different part designator letters. For example use "R" for a 10k resistor and "TR" for a 10k thermistor
  • Include the tolerance (or whatever the necessary difference is) in the value field: 2 resistors could be "1k 5%" versus "1k 0.01%"
  • \$\begingroup\$ How do you "combine the parts"? \$\endgroup\$
    – topher217
    Apr 25, 2022 at 2:02
  • \$\begingroup\$ @topher217 Just decide that they are identical and always use the first one and don't use the 2nd. \$\endgroup\$
    – Casey
    Apr 26, 2022 at 23:38

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