How to find out the efficiency of an aluminum electrolytic capacitor like this one.
How to find out resistance of such a cap in order to calculate the time it takes for it to charge up or discharge?
The resistance would also allow to account for power loss as stated above. Is there any hint in the datasheet enabling me to calculate the desired values?
@ Christian B: Thank you but the ESR or dissipation factor is given just for 100 Hz. What if I wan to discharge the cap just once a day (-> low frequency)?
$$ESR = tan\delta * \frac{1}{2\pi fC}$$
If I assume f = 1 Hz for example and C = 2 mF, I will get approx. an ESR = 10 Ohm. But assuming f = 1 Hz seams not reasonable to me though.
@ Marcus Müller: The efficiency I am looking for is basically the equivalent ohmic resistance during charging and discharging. Once having that number, together with charge/discharge time and current/voltage, I could calculate the power dissipated in that resistance. Of course the leakage current is important too. At least when the cap stays charged for "longer time".
Or is there a different approach? I simply want to intermediately store energy in that cap.
I_leakage-after-2-min-at-U_R< 0.01 x C_R x U_R
. So with 2.2 mF and 10 V we are talking about I < 0.22 mA (which is actually given in the table as well). So comparing the charge with the discharge current we are talking about seconds to minutes in the worst case scenario. If you want to make it super correct you can use an exp function with a decay constant of 0.01 * 0.0022 if I am not mistaken. \$\endgroup\$