This is most likely a dumb question, just for some reason I have just forgotten the fundamentals about how charging and discharging work.
When the switch is closed the inductor keeps charging and when it is opened it discharges through the diode. Now here is my question. Why doesn't the inductor keep charging as the current is entering back through the inductor? This is the fundamental knowledge I have forgotten.
Is it due to the diode voltage drop? Hence charge out is always less than charge in? (I know its a bit of a dumb question but I would like to just clear my confusion).
Also if the diode wasn't there and say the inductor had charge in it already (the switch is open at this time) and say the diode shorted completely, no charge will be lost will it?
****In short what causes an inductor to discharge again and how does it discharge through itself (when the switch is open). Does it discharge through itself due to internal resistance or no? ****