4
\$\begingroup\$

I would like to reassure my concept on this question:

Question

I have 2 different ways to solve this question:

  1. Determining the direction of current in the loop using right-hand solenoid loop and adding them up to get \$2I\$. With option C as the answer.

  2. Because all the wires are in 1 closed loop with the same direction, we should just add them up together to get a total of \$6I\$. With option E as the answer.

\$\endgroup\$
  • 1
    \$\begingroup\$ In "1.", the intuition that the wire carrying 2I goes through the loop in the other direction is correct. The wire didn't turn around, but the loop did. The reasoning in "2." is wrong for the same reason. \$\endgroup\$ – Andrew Macrae May 15 at 16:37
4
\$\begingroup\$

I'd go with 3l+l-2l, if you rotate the middle current and loop so they all look alike it looks like this: enter image description here

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.