If two identical diodes are in parallel and forward biased such that their anodes are at the same potential but their cathodes are at different potential how can we find the anode potential?
I can simulate this and figure out what V6 is but I tried to find myself and puzzled.
First of all the diodes are identical and the diode on the left is reverse biased so it is out of the picture.
Now if only the diode with -6V cathode voltage existed V6 would be -5.4V. And if only the diode with -12V cathode voltage existed V6 would be -11.4V. My logic here is that the voltage drop must be 0.6V so one can find the anode terminal voltage by adding 0.6V to the cathode voltage. And both diodes are forward biased.
But when their anodes are tied together there must be only one voltage at that node V6. I have been thinking about it but probably missing a point. How should we approach this topology to figure out the voltage at V6?