Let's say we have an energy band diagram of a BJT at equilibrium. Then, we apply -0.7V to BE, while 0.7V is applied to BC.

How will these voltages affect the band diagram? I would appreciate it if someone can point me in the correct direction. Is it as simple as lowering the band diagram on the BE side and raising it on the BC side?

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    \$\begingroup\$ And what, probabibilistically, does altering the bandgaps achieve toward changing the current flows? I think this --- the probabilities --- explains the transistor behaviors. \$\endgroup\$ – analogsystemsrf Jun 8 '19 at 11:55

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