0
\$\begingroup\$

I'm trying to design and simulate the Q-modulation technique for a body implant. The technique involves two loops: one outside the body, with resonating LC tank producing a big voltage. Another loop is inside the body and has coupled links.

I need to switch load in the second loop to improve my efficiency. I used an ideal switch at first. It works fine after I replace the switch with a mosfet. However, in OFF phase of Mosfet, body diode will turn on, and the negative current will flow through mosfet. This is bad for efficiency and power consumption,

Help me get rid off this negative current.this photo will help undretand what i said Frequency: 13.56 MHz

\$\endgroup\$
  • \$\begingroup\$ Do you mean MHz when you put meg? \$\endgroup\$ – Solar Mike Jun 16 '19 at 16:04
  • \$\begingroup\$ Try switching the load after the diode. Also, if you parallel tuned the receive coil you could use abridge rectifier I reckon. \$\endgroup\$ – Andy aka Jun 16 '19 at 16:14
  • \$\begingroup\$ Not sure I understand everything but you could try to connect two MOSFETs back-to-back: electronics.stackexchange.com/questions/178526/… \$\endgroup\$ – Verbal Kint Jun 16 '19 at 17:56

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.