If I send a signal through a wire having delay of 10ms, then should I need to maintain the source of the signal till it reaches the destination or can I change after, say, 2ms and send the next signal. The 1st signal reaches destination at 10ms and 2nd signal reaches destination at 12ms.

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    \$\begingroup\$ No, the propagation delay is irrelevant. If you are sending a digital signal then there will be a defined bit time for the signal, and you must obviously meet that. \$\endgroup\$ Jun 17 '19 at 3:03
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    \$\begingroup\$ Consider that we routinely send 1 Gbps signals over distances much longer than 30 cm. \$\endgroup\$
    – The Photon
    Jun 17 '19 at 3:55
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    \$\begingroup\$ Have you ever watched satellite TV? If what you are saying were true, you could only send one signal every 250ms. Assuming that were only interested in black and white, and we are using standard resolution (not HD or 4K), then we could transmit about 4 pixel per second, or about 1 frame per day. So, if you have ever watched satellite TV at a frame rate of more than frame per day, you know that this cannot be true. (Note, I am assuming a simple analog encoding.) \$\endgroup\$ Jun 17 '19 at 12:57

Years ago I designed a video system that sent a composite video signal down a coax cable from the video controller to the display CRT. This system used monochrome video with a 20MHz dot clock to display text and graphics on the CRT.

Note that at 20MHz each pixel of video was 50ns wide. At the time the typical font used on the CRT was 5 pixels wide and had a 6th pixel of spacing to the next character. Thus the total width time for one character on the screen was 6 * 50 = 300ns.

During system testing we wanted to check the integrity of the video signal over a length of coax cable that would be maximal in comparison to the typical installed application of the system. So one day we traveled to a large surplus electronics outlet and purchased a large wooden spool that had about 450 feet of coax cable on it. (It was rather entertaining to other building occupants when we rolled the spool down the halls to our suite in the office building).

When we tested the cable system we placed two channels of our DSO (digital storage oscilloscope) with one channel displaying the video driver feeding into the coax cable and the other channel displaying the signal coming out of the coax cable at the receiving CRT. The scope was triggered off the trailing edge of the vertical blanking signal so that we could capture the video signal for the left edge of the very first scan line. The video was setup to display two "H" characters as "HH" on the first row of characters.

The video signal for the top row of pixels of the displayed characters could be depicted as follows with X representing active video and _ representing off video:

X___X X___X

When displayed on the scope waveforms looked like the following:

enter image description here Picture fabricated in Visio

Channel 1 (upper trace) was the cable input and Channel 2 was the cable output. The signal transit time down the cable was approximately 600ns or just short of 1.5ns/foot.

So the short answer to the question is that, No it is not necessary to maintain the input signal to a transmission line until the current edge arrives at the far end.

It is interesting to note that analogue oscilloscopes often have a coil of coax inside is used to delay the signal from the input section to the display section. The intent being that it allows the very first part of the signal to be displayed on the left side of the screen relative to the trigger signal moving the electron beam to the left edge of the CRT.

  • \$\begingroup\$ Sophomore year electrical engineering transmission line lab experiment -- you're given a coiled cable and required to measure its length without uncoiling it. \$\endgroup\$ Jun 17 '19 at 16:52
  • \$\begingroup\$ @RobCrawford = Interesting university lab experiment. We never had that back in '71, '72 or '73 in my EE labs. I guess I did it in the '84 time frame when the above described experiments were done. \$\endgroup\$ Jun 18 '19 at 6:07

Hopefully, this picture should explain: -

enter image description here

Picture taken from here.

The spring represents the media in which a signal can travel. The signal can be a voltage/current or an electromagnetic field or, just a mechanical spring with someone shaking one end.

An impulse is applied to the spring and, as you should be able to see, it passes through the media from left to right. It's exactly the same with a signal passing down a cable or a radio signal transmitted from a satellite in orbit or light from a distant star; once an impulse of power or energy is fed to the media, it propagates through that media and is unaffected by what may come afterwards.

Think of dropping a stone into water - the resulting wave continues to expand outwards: -

enter image description here

This is pretty much exactly how a radio wave impulse propagates from an antenna. Picture taken from here.



If that were the case, we couldn't do much communications at all.

I don't know how to counter this (it seems completely unfounded) other than making an analogy.

You don't need to wait for the reader of a book to finish reading the first letter to print the second.
You can deliver all the letters at once – the only thing important is that they arrive in the same order.


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