enter image description here

Can anybody please explain why the voltage source has been short circuited here after the switch has been closed at t=0. Thank You.

  • 1
    \$\begingroup\$ With voltage source, they mean: the voltage source with the 2 \$ \Omega \$ is in series. I agree they are technically incorrect saying the voltage source is short-circuited. Does this help you understand it? \$\endgroup\$ – Huisman Jun 20 at 7:02
  • \$\begingroup\$ Alright, voltage source with 2ohm in series. But why? What's the logic here? \$\endgroup\$ – Yash Gupta Jun 20 at 8:52
  • \$\begingroup\$ No idea. Maybe the 2ohm resistor should represent the internal resistance of the voltage source? \$\endgroup\$ – Huisman Jun 20 at 9:03

Since there is a short circuit, the complete voltage drops across the 2 ohm resistor. Since current only passes through the short circuit and not through the path which offers a resistance.

The short circuit completely isolates the voltage source and 2 ohm resistor from the rest of the circuit.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.