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Can anybody please explain why the voltage source has been short circuited here after the switch has been closed at t=0. Thank You.

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    \$\begingroup\$ With voltage source, they mean: the voltage source with the 2 \$ \Omega \$ is in series. I agree they are technically incorrect saying the voltage source is short-circuited. Does this help you understand it? \$\endgroup\$ – Huisman Jun 20 at 7:02
  • \$\begingroup\$ Alright, voltage source with 2ohm in series. But why? What's the logic here? \$\endgroup\$ – Yash Gupta Jun 20 at 8:52
  • \$\begingroup\$ No idea. Maybe the 2ohm resistor should represent the internal resistance of the voltage source? \$\endgroup\$ – Huisman Jun 20 at 9:03
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Since there is a short circuit, the complete voltage drops across the 2 ohm resistor. Since current only passes through the short circuit and not through the path which offers a resistance.

The short circuit completely isolates the voltage source and 2 ohm resistor from the rest of the circuit.

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