Does the Resistor have an impact to the electric charge of the capacitors?

I have this circuit (picture below) and at first I had to calculate the eletric charge of the capacitors without the resistor which is parallel to C1. Which was not a problem at all. After that the resistor came up parallel to the C1 and I should calculate the electric charge again for both capacitors. The voltage is DC and the electric charge for t -> infinity.

I'm not sure how to calculate it because I think the resistor does not change anything.

Here the circuit:

• Think about it. Initially uncharged (perfect) capacitors are shorts. Then, after an infinite amount of time they open. – st2000 Jun 22 at 23:28
• R1 at t>infinity effectively nullifies C1. C2 then sees the full 800V. – vini_i Jun 22 at 23:31
• The DC current of a capacitor is zero. Apply KCL and Ohms law to R1. – sstobbe Jun 22 at 23:34
• So the Q = C*U of C1 is zero? At beginning when t=0 both capacitors charge and after a amount of time the C1 discharges through R1 and therefore the charge of C1 gets zero again? Is that right? – Manuel Jun 22 at 23:39
• Stop! Answering! In! Comments! Gah. – pipe Jun 22 at 23:39