# How to convert T matrix to Z matrix in two port network?

How can I transform a T matrix to become a Z matrix for a two-port network?

I found the following conversion to get the T matrix from Z matrix from here: Two-Port Parameter Conversions

Step 7 - Therefor, the T parameters matrix is
$$\begin{bmatrix} A & B\\ C & D \end{bmatrix} = \begin{bmatrix} \frac{Z_{11}}{Z_{21}} & \frac{Z_{11}Z_{22}-Z_{12}Z_{21}}{Z_{21}}\\ \frac{1}{Z_{21}} & \frac{Z_{22}}{Z_{21}} \end{bmatrix}$$

But I would like to get the opposite of this. To go from T matrix to Z matrix

• Just do some algebra. If you look at it for a minute you should be able to figure this out on your own. Commented Jun 29, 2019 at 14:41
• This page clearly provides the definitions of each type. Since they already provide you with the answer for $Z\rightarrow T$ and from the page I've linked you know the independent definitions of $T$ and $Z$, you should be easily able to see how they arrived at the transformation they provided on the link you gave. Knowing that much, it should be a walk in the park to do the reverse. Do you follow how they derived $Z\rightarrow T$? If so, there are no problems. If not, focus on their derivation first.
– jonk
Commented Jun 30, 2019 at 5:18