# Pulsed Power Charging Resistor and Choke

I am currently attempting to build a pulsed power supply that requires an 8 H inductor to produce 50 kV 17 A square pulses with widths of 100 uS. Please see the attached schematic for more details (unfortunately, the load is comprised of a gas ionizing device, thus, the resistance fluctuates quite unpredictably).

Due to the obscurely high inductance required, I have considered using a charging resistor instead. However, I am unsure of how to find the exact resistance that will be needed to match the pulse-limiting capabilities of the 8 H inductor. How many I calculate the needed resistance?

simulate this circuit – Schematic created using CircuitLab

• A capacitor discharge schema like this will NEVER produce a square wave output since it operates using the ringing of C1,L1 and the transformer inductance. Can you explain your needs (specification) somewhat better? – Jack Creasey Jul 4 at 15:35
• Greetings, the purpose is to use the above apparatus to provide 10 pulses per second where each pulse has a pulse width (lasts for) 100 uS and has a voltage of -50 kV and current of 17 A. These are the only absolutely necessary needs. I agree that it won't be perfectly square, however, I will try to keep the gauges as high as possible on the transformer to get it to have a fast lead time. As for the goal, I am curious what value of resistor could replace L1 to give me the pulse width and frequency I had mentioned earlier. – Super Nerds Team Jul 4 at 15:46
• The pulse rate is set by your thyristor pulses of course, your only limitation s how fast you can charge C1. That is a simple RC delay problem: mustcalculate.com/electronics/… – Jack Creasey Jul 4 at 16:11
• Too quite on the Enter key. Your bigest problem is the power in the resistor if you are really using a 1uF storage capacitor. Have you done any calculations at all on what you want to achieve? – Jack Creasey Jul 4 at 16:15
• Greetings, nothing yet for the resistor because I do not have the required equations/knowledge to do so. Currently, this model is copied from an older design used for a similar load. There is someone advising me on the rest of the device, however, he is away at the moment and I want to find out what is required for the resistor. The rest, however, was said to work. – Super Nerds Team Jul 4 at 16:20