# Switching between battery and external power sources with reverse polarity protection

In my design, I will use AA batteries to power the electronics board. As a requirement, also it should accept the power from external power supply (12V) - The board should automatically switch from battery to external source. - The board should have reverse polarity protection for both battery and external source.

I found this solution from Maxim Integrated..

FET switch can reduce the drop to less than 0.1V instead of diode.

My Question: The FET (FDN340P) and diode (1N4001) work as reverse polarity protection for board?

• datasheets.maximintegrated.com/en/ds/MAX6326-MAX6348.pdf Jul 6, 2019 at 21:14
• MAX6326 is up to 5.5V thus this solution will not work with 12V. Also, lowest Vcc voltage is -0.3V so MAX6326 must be protected itself. Jul 6, 2019 at 22:29
• Regarding protection against polarity reversal only, this [Application Report] (ti.com/lit/an/slva139/slva139.pdf) from Texas shows some reverse current / battery protection circuits. Jan 31, 2020 at 16:33

The board should have reverse polarity protection for both battery and external source...

My Question: The FET (FDN340P) and diode (1N4001) work as reverse polarity protection for board?

No.

In this circuit the MAX6326 is powered directly from the external source. Absolute maximum input voltage rating is -0.3V to +6V, so reverse polarity will kill it. And you require the circuit to accept 12V, which will also kill it. There is no simple solution to this problem.

Reverse battery protection is also iffy. If the battery is connected in reverse with external power off then the FET's internal body diode will stop the reverse voltage from getting to the output. However if external power is then applied the FET will turn on for at least 100ms until the MAX6326 comes out of reset. During this time a very large current will flow from the external power supply into the battery. The components will probably survive this momentary surge current, but the high stress could reduce reliability.

Given the problems with this circuit you will have to look for other solutions that don't involve a MAX6326. The simplest is to just use a Schottky diode in place of Q1. If you choose a high current Schottky the voltage drop could be less than 0.3V. If this is too much then just add another cell to the battery to make 4.5V, then a standard silicon diode will do the job.

In this schematic D1 together with R1 ensures that voltage on pin U1.3 is 0V so that U1 would keep Q1 open until there is a voltage source on External Power. Q1 is there to disconnect batteries from load.

That circuit does not provide full reverse polarity protection from the batteries

but it's hard to connect AA batteries in reverse

also at low supply voltages it may not prevent charging