Can you help me on understanding why we may say this transmission line the propagation is guided and there is not any radiation?

enter image description here

It is a 2-conductors transmission line, in which the conductors are assumed to be at a very low distance. My textbook assumes that the line is open, and says that, since the currents on the wires are opposite, the EM fields cancel each other.

But, I do not understand some things:

1) How can I "see" (graphically) that tue EM fields cancel each other?

2) And if was the transmission line connected to an impedance Zl?


That is just a very schematic drawing. You can't "see" that this is a transmission line. The text just defines it to be.

  • \$\begingroup\$ Do you know how to find something about this? Maybe an image or some explanation of this phenomenon \$\endgroup\$ – Kinka-Byo Jul 9 '19 at 15:43
  • \$\begingroup\$ There's no phenomenon here! Just a book that says "look at these two black lines: imagine they are a transmission line". end of story. \$\endgroup\$ – Marcus Müller Jul 9 '19 at 16:24
  • \$\begingroup\$ Yes, but in theory it wanted to show that a transmission line does not irradiate, although there is not any graphical explanation \$\endgroup\$ – Kinka-Byo Jul 9 '19 at 17:32
  • \$\begingroup\$ I don't know whether you can meaningfully prove that at all, that's the definition of a transmission line: Find a construct in which a specific EM/TEM wave can only propagate in one direction. You call that a transmission line. \$\endgroup\$ – Marcus Müller Jul 9 '19 at 22:29

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