# Chua's circuit's equilibrium at $x=y=z=0$

The Chua's circuit satisfies the differential equations from Wikipedia. Clearly, $$\x=y=z=0\$$ is a solution, but not the solution we see when double scroll appears. Since at $$\t=0\$$ when we switch on the circuit, $$\x,y,z\$$ must be all very close to $$\0\$$, for double scroll to appear, the system must be able to walk away from $$\0\$$. Therefore, $$\0\$$ must be an unstable equilibrium if the experiment is successful.

However, whether $$\0\$$ is an unstable equilibrium or not depends on the parameters. So does it mean that, if the parameters are incorrectly chosen so that $$\0\$$ is a stable equilibrium, then no double scroll can be observed?

• Double scroll? Define it Jul 13, 2019 at 4:59
• This question appears to be a duplicate of one posted on physics.se. Please don't cross-post on different SE sites. If you've decided that EE is a better site for this question, you can ask the Physics mods to migrate your question over here. Jul 13, 2019 at 5:27
• @laptop2d See the picture on wikipedia. Jul 13, 2019 at 6:10