The Chua's circuit satisfies the differential equations from Wikipedia.

enter image description here

Clearly, \$x=y=z=0\$ is a solution, but not the solution we see when double scroll appears. Since at \$t=0\$ when we switch on the circuit, \$x,y,z\$ must be all very close to \$0\$, for double scroll to appear, the system must be able to walk away from \$0\$. Therefore, \$0\$ must be an unstable equilibrium if the experiment is successful.

However, whether \$0\$ is an unstable equilibrium or not depends on the parameters. So does it mean that, if the parameters are incorrectly chosen so that \$0\$ is a stable equilibrium, then no double scroll can be observed?

  • 1
    \$\begingroup\$ Double scroll? Define it \$\endgroup\$
    – Voltage Spike
    Jul 13, 2019 at 4:59
  • \$\begingroup\$ This question appears to be a duplicate of one posted on physics.se. Please don't cross-post on different SE sites. If you've decided that EE is a better site for this question, you can ask the Physics mods to migrate your question over here. \$\endgroup\$
    – The Photon
    Jul 13, 2019 at 5:27
  • \$\begingroup\$ @laptop2d See the picture on wikipedia. \$\endgroup\$
    – Jethro
    Jul 13, 2019 at 6:10


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.