So we were given this circuit to solve for I1, I2, I3, and lastly the Thevenin Equivalent Circuit. I was able to solve for I1, I2, I3. However I am having a hard time computing the RTH at ab.
Here is the circuit I was trying to use to find RTH.
\$\begingroup\$
\$\endgroup\$
9
-
\$\begingroup\$ OK, what's the issue with the Rth that you were trying? Where are you stuck? \$\endgroup\$– John DJul 23, 2019 at 17:55
-
\$\begingroup\$ I can't figure out how to solve it since there is short curcuit at the left side. \$\endgroup\$– RaneJul 23, 2019 at 18:08
-
1\$\begingroup\$ That's not a "short circuit", it's just a connection between the top and bottom nodes. \$\endgroup\$– Elliot AldersonJul 23, 2019 at 18:20
-
1\$\begingroup\$ Perhaps redraw the circuit in a more familiar way. \$\endgroup\$– TylerJul 23, 2019 at 18:31
-
1\$\begingroup\$ Think about @Tyler's suggestion. What do you know about components that have the same voltage across them (because they are connected)? \$\endgroup\$– John DJul 23, 2019 at 19:41
|
Show 4 more comments