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I know there are lots of similar questions and read them, but I need a simpler and clearer answer.

I understand why and how to use a pull up/down resistor when using a button (GPIO input). But while configuring a GPIO pin which will be connected to an LED, what is the use of these settings?

I tried no pull-up and pull-down and pull-up for example, but I could not see a difference in the implementation.

I am using STM32F407-DISC.

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Reset to default
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The pull up/down is only effective in Input or Open Drain configuration.
When set as output there is always an output MOSFET active, the pull up/down is then wasting energy.

The exception is open drain mode, this disables the P-MOS, then pull-up can be useful again.

Figure 25. Basic structure of a five-volt tolerant I/O port bit

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  • \$\begingroup\$ But the raising edge will be quite slow with the internal (on chip) pull-up resistor(?). \$\endgroup\$
    – Peter Mortensen
    Jul 29, 2019 at 19:38
  • \$\begingroup\$ @PeterMortensen Yes. It's ~40 kOhm. But if it's all you've got then it's at least something to keep the pin in a defined state. \$\endgroup\$
    – Jeroen3
    Jul 29, 2019 at 20:17

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