I'm testing out different circuit simulator programs and I was able to build the integrated circuit SN74LS245 Octal Bus Transceiver in a program called Digital Works. Here is the datasheet SN74LS245 pdf.

In Digital Works you set up the logic gates that you need, and for the pin I/O in this application it has a tag device in which you can associate that tag as an external pin to the IC. In Digital Works, I'm able to save this circuit and its template as a macro and then be able to include that into another circuit.

Within Digital Works I was able to create an 8 bit bus and connect multiple devices to it using this 74LS245 chip. I can use the ~OE pin which is active low to allow the chip to be either active or inactive to the bus. I can then use the DIR pin to set the direction of the I/O. If DIR is set HIGH or 1 then logic will flow from pins [A1..A8] to pins [B1..B8]. If DIR is set to LOW or 0 then direction flows from [B1..B8] to [A1..A8]. This is the desired and expected behavior of this chip.

I will show some screen shots of the logic implementation and the different simulated states it can be in.

Here is the logic diagram within Digital Works when all of the pins or external connections are defaulted to 0 or LOW input. This is the internal design of the IC macro circuit.

74LS245 Logic

Now I'll show you a series of images in it's different states: I'll only be using 4 pin I/O's for this demonstration. I will have A's bus inputs as 0011 and I'll have B's inputs as 1100 just to show how it only flows in a single direction or doesn't flow at all or disconnects when ~OE is set to HIGH. First here is the truth table of the 4 states:

~OE  | DIR | BUS A - in | BUS B - in | BUS A - out | BUS B - out
 0   |  0  |    0011    |    1100    |    1100     |    1100
 0   |  1  |    0011    |    1100    |    0011     |    0011
 1   |  0  |    0011    |    1100    |    0011     |    1100
 1   |  1  |    0011    |    1100    |    0011     |    1100

Here are the 4 images of the respective states:

State A

State B
State C
State D

I tried to do the same thing in Logisim but I'm having issues with it's pins for I/O. It seems that Logism is expecting for it to be either an input or an output. However, there is an option to set it to 3 states, but I'm not getting the desired behavior that I am seeing within Digital Works. Can this type of circuit with bi-directional capabilities be simulated within Logisim? If so; how would one do this, what am I missing or over looking?


3 Answers 3


I know this post is pretty old, but may be somebody is still interested. Indeed, it is not possible to really simulate the 74245 with Logisim : in a subcircuit, a pin may only be an input OR an output, not both, as opposed to the real 74245.

But it can be simlated pretty easyly. First of all, you design it as a subcircuit, where for each pin A1, B1, 12, B2 etc. you create 2 pins : one input, one output :

fake 74245

Then, you can build your circuit with it. In the following, its a typical usage where you interface a data bus with a register.

sample use

When FROM A TO B is set to one, you can write some value on the bus using the BUS INPUT pin, then assert the bus. Signals are going from a to B. When done, you just push the button below the register to store the value. Then you can stop asserting the bus, and switch FROM A TO B to zero : one can see that now, the bus is written from B to A.

Not perfect, but the easiest I can think of to "simulate" the 74245.


I made a subcircuit as shown in the figure below.

74245 Bus transceiver

If you create a subcircuit that connects the same inputs and outputs as the 74245 data sheet, it will not work properly. Instead, I defined the input and output pins separately and connected the inputs and outputs in the main schematic to accurately simulate the expected behavior.

Both input and output pins should have the three-state attribute.


Your test circuit looks as though it's driving the pins on both sides of the simulated IC. This won't work -- you need to disconnect the drivers (square with circle inside) on the side that's currently being used as an output.

Digital Works appears to be handling this situation incorrectly by allowing the output of the IC to override the output of another driver with no warning. Logisim will (correctly) warn you when this occurs -- a simplified version of your test circuit yields:

enter image description here

  • \$\begingroup\$ It has tri state logic within the circuit. If the OE pin is set low the chip is enabled and the direction of the flow will depend on what the DIR pin is set to high or low. If you look at the images that are from Digital Works; you will see that the lines that are black are active high and the lines that are grey are either active low or disabled... \$\endgroup\$ Commented Jul 30, 2019 at 23:26
  • \$\begingroup\$ No, I mean in the circuit outside the IC. Every indicator (circle thing - LED?) is connected to a driver, which is actively driving the signal high/low regardless of whether the IC is also trying to drive that signal or not. \$\endgroup\$
    – user39382
    Commented Jul 30, 2019 at 23:28
  • \$\begingroup\$ In the first image the led's on the left that are lit up are coming from the b-side bus, and the pressed buttons on the left are still on but the led's are off when the DIR is low, in the 2nd image when DIR is high, it's just the opposite. \$\endgroup\$ Commented Jul 30, 2019 at 23:29
  • \$\begingroup\$ This works fine in Digital Works because of the tri state buffers within the IC, follow the logic! If Enable is low then the and gate on the right side is active and it is sending a 1 to the left side and gate. This activates the line going all the way down on the right side that is connected to the tri state buffers' enable line. When DIR is low, it will drive the flow from B to A. When DIR becomes HIGH or 1, It turns on the left line all the way down, and turns off the right line all the way down making flow go from A to B. \$\endgroup\$ Commented Jul 30, 2019 at 23:35
  • \$\begingroup\$ The images above are showing that the simulated circuit works within the application Digital Works. The buttons that are connected to the LEDs are what is driving the values across the wires. \$\endgroup\$ Commented Jul 30, 2019 at 23:37

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.