# Current flowing in an open circuit to make it the same voltage

I've tried to research this answer for quite some time but i'm struggling to find a proper answer. I think my question falls between antenna theory and batteries.

So in a dipole antenna we supply a sine wave across the antenna and this generates a small current due to capacitance and the electron flow at that frequency.

Now suppose we take this example to a DC circuit I understand DC current cannot flow in an open circuit because the battery has a net neutral charge and if you just discharge one side the other side creates an electric field to pull the discharged side back.

But if put that battery across two huge metal blocks one on each terminal will you get a current flow as one side has electrons added and one side electrons removed? As I understand for one side to be at +12v it must have a lack of electrons and the other side a surplus so there must be some electron flow to make each block equal to the voltage? Otherwise my understanding of the antenna doesn't seem to make sense.

Then theoretically if you charge one block to 12V and one block is at 0v then disconnect the battery what happens to the charges on each block?

• FYI, sometimes we talk about the transient behavior of a circuit. That is, what happens when we suddenly change something (like, what happens when we switch on the power.) Other times, we want to talk about the steady state behavior of a circuit. The rule that says, "current cannot flow in an open circuit" belongs to the realm of steady state analysis. A capacitor is an "open circuit," and a capacitor can't conduct steady DC current, but you'll get a big spike of inrush current (a transient) when you first connect your capacitor to a DC power supply. Commented Aug 6, 2019 at 18:54