# Why is this circuit causing my breaker to trip?

I'm an electronics hobbyist and I decided to make my own electric heater/kiln thingy. It works fine for a couple of minutes, but then the breaker trips. This is my first project involving AC, so I'm a bit clueless as to what could be happening here.

The circuit is very simple:

• I have a coil of wire that is switched on/off by a SSR which is controlled by a PID controller.
• The PID and the heater coil each have their respective fuses.

• I'm run it off a wall outlet and since I live in Canada, it operates at at 120V AC 60 Hz.

• I have it grounded to the heatsink of the SSR, which is housed close to all the other wiring, but definitely not touching.

Edit: I hope I didn't botch this circuit drawing, but here it is.

simulate this circuit – Schematic created using CircuitLab

My thoughts:

1. The breaker cannot be tripping from over-current because the fuses are never blown, and the wire itself can only handle a maximum of 5 amps before melting. (I think the breaker trips at 10 or 15 amps).
2. Is it possible that the coil is generating a voltage spike that is arcing over to ground? Like how in DC, the voltage builds up as the field collapses.
3. If 2. is a possibility, how would prevent that from happening? Like how in DC you would have a fly back diode.

That's all I could think of, and honestly I don't know what to look up so I decided to ask here before turning it back on again.

Thanks.

PS: I decided not to draw a circuit because I don't know what the exact values would be for all of the components. I'm hoping that the circuit is simple enough to understand from the description in words. I can attempt to go calculate everything if it's really necessary, just hope I don't have to haha.

• a wire under water will handle hundreds of times more current than the same wire in air. if your breaker pops, it's because you're using too much current, unless you have a brand-new breaker with AFCI, but that's not likely the case, or cause even if true. Aug 21, 2019 at 20:53
• Fuses don't actuate instantly. Circuit breakers are generally faster, depending on the type. Aug 21, 2019 at 20:56
• Measure the resistance of the heater, calculate the current flow and post the information into your question. Aug 21, 2019 at 20:59
• Draw a schematic, and note where you don't have values. The drawing is in any case better than words describing a circuit. Just make sure the drawing correctly represents the circuit.
– JRE
Aug 21, 2019 at 21:19
• As said above, picture(s) would be very helpful. There may not be a 'problem' with your circuit, but a problem with the design. As transistor rightly said, surely you have an idea of the current drawn from your heater, and you are asking this question as the current is much higher than you anticipated. If not, you will probably need to measure / post some component / circuit values. Aug 21, 2019 at 21:32