Could someone explain the voltage readings on the following "oscilloscopes" of the simulated schematics below:

(I understand the concept of a voltage divider but it seems something less straightforward is happening here)

To be clear, the top source is 12V DC and the lower one is 6V DC. All resistors have the same value.

The first one is simpler:

The second one adds a slight complication:

Sorry for the large size of the photos. I couldn't figure out how to resize them.

• hmm that makes A LOT of sense. The derivation of the voltage divider equation is indeed dependent on the same current flowing through the resistors in series... or at least nearly equal as you said. That explains a lot because I was using this question to understand a much more complicated circuit - I guess if the 6V source was something like a high impedance line level instead ($\approx$ 1.7V amplitude AC, 10k input impedance) then do you think we could treat the 12V source as effectively voltage divided? – Andrew Aug 23 at 12:00