1
\$\begingroup\$

I have a +3.3V voltage rail available. And I want to generate a pair of negative and positive symmetrical supplies out of it. The magnitude of the output voltages must be less than 7V and should be higher than 5V; anything around 6V is fine.

These voltages will supply a couple of analog switch ICs, which will consume current around 50mA at total from the both supplies rails. My charge pump controller IC (MAX1720) itself can supply that much of current, but its output voltage drops down to undesirable levels when that much current is drawn. So I decided to enhance the output stage by using a NPN/PNP pair as suggested in the datasheet (page 14, figure 42).

My Circuit

I have no problem with the design of the positive voltage doubler circuit. But, the datasheet doesn't suggest any way of increasing the output current capability for the inverting circuit. Can I do the same thing in the inverting one. If yes, how do I do it?

\$\endgroup\$
2
  • \$\begingroup\$ Analogue switch consumption will never be 50 mA unless you are doing something really wrong. On the other hand the analogue switch might be switching 50 mA. Please be clear. \$\endgroup\$
    – Andy aka
    Commented Aug 28, 2019 at 15:19
  • \$\begingroup\$ @Andyaka There are four of them and the current consumption values I wrote are the maximum values in the datasheet. \$\endgroup\$ Commented Aug 29, 2019 at 5:12

1 Answer 1

1
\$\begingroup\$

It isn't the transistors that are limiting the current, it's the capacitors. A capacitor of a given size (and a fixed supply voltage) can only transfer a certain amount of charge per switching cycle, and that charge, multiplied by the switching frequency, becomes your output current.

The only way to increase the current (keeping everything else constant) is to use larger capacitors.

\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.