What represents this formula in terms of an RLC series circuit that forms a resonator? It is called figure of merit and it is defined like this:

M = 1/ w*C1*R1

where w = 2*pi*f

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  • 1
    \$\begingroup\$ Do you mean the resonator Q? \$\endgroup\$
    – TimWescott
    Aug 30, 2019 at 20:06
  • \$\begingroup\$ yes, I edited the question. Thanks! \$\endgroup\$
    – tairit
    Aug 30, 2019 at 20:09

1 Answer 1


Your equation for figure of merit M, AKA the Q of the circuit, is correct as long as you recognize that \$f\$ is the resonant frequency, and \$C\$ is the capacitance that sets the resonant frequency. In this case the resonant frequency is set by the motational capacitance and inductance, \$C_1\$ and \$L_1\$.

So \$\omega = \frac{1}{\sqrt{C_1 L_1}}\$, and \$Q = \frac{1}{\omega C_1 R_1}\$.


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