# Determine the output signal given the input and inpulse response

It's been a while since I've worked these types of problems, but I've been working out the following problem for a while now and can't figure out a few details:

And here is the solution:

Most of the solution makes sense, but I just have a few things I'm not able to clarify, namely:

1. How were they able to determine the h(t) is a low pass filter? And which fourier coefficients will be passed through? Seems like n=2=-2 should be a valid coefficients too

2. How did they get h(t) into the frequency domain?

*Update:
For the aspect of getting h(t) into the frequency domain, I've attempted the following but it doesn't line up with the what's given in the solution:

Any help is appreciated

How were they able to determine the h(t) is a low pass filter?

Specifically, they noted that the time-domain response of the filter is of the general form $$\\frac{\sin(x)}{x}\$$, with some scaling factors for both time and amplitude.

"Everyone knows" (but you may have forgotten) that the Fourier transform of a sinc function is a single rectangular pulse centered at the origin, which means that the frequency-domain response of the filter is an "ideal" or "brick-wall" low-pass filter. Such a filter passes all frequencies below its cutoff frequency, but none at all above that frequency.

They then proceed to identify exactly what its cutoff frequency is.

Note that this filter is "non-causal" — its time-domain response extends infinitely far into the past, so it isn't physically realizable.

• Hi Dave Tweed, thank you for the additional info. I've dug out my old Signals&Systems book and things are started to come back to me. However, In attempting to get h(t) into the frequency domain, I've arrived at a solution that differs from the correct solution. I've added an update to my question and was hoping you could provide some further insight. Thanks again – InterestingGuy Sep 2 '19 at 19:00

By noticing that there exists some frequency $$\\omega_x\$$ for which $$\H(\omega) = 0\$$ for all $$\\omega>\omega_x\$$.