I have some confusion about the negative terminal of a capacitor. Consider the following
Now, my understanding was that postive charges accumulate at the positive ("top") plate of the capacitor, setting up an electric field within the capacitor which causes negative charges to accumulate at the bottom plate.
Does that mean that the bottom plate of the capacitor will be at -5V eventually (at steady-state). Or does it mean it will still be 0V? The circuit simulation tool I ran this with, says it is 5V.
Can someone explain what the negative plate voltage is? And also what happens if there was no ground but another circuit component there?