I am trying to create a power-on delay with a 555 timer IC. I have never used one of these before and I am finding it a bit tricky to make applications with it - a lot going on.
My question is in relation to the power-on delay circuit (first picture) above. Initially the 100uF capacitor is fully discharged (0V) , so doesn't that mean that the trigger pin will be low (less than 1/3 Vcc) and thus the flip flop will get set high and thus cause the output to go high -> defeating the entire purpose?
Secondly, how is it possible to measure the 100uF capacitor voltage from the negative terminal, wouldn't that always be 0V?
Is it just me or are these circuits hard to understand at first?