# Simple circuit with an inductor in transient state

I have a problem with this circuit. I am supposed to calculate i(t) at the moment t=(0+). The parameters are:
R=300Ω
e(t)=12V
L=0.1H
Switch is closed at t=0

I know that current can't jump in the branch with the inductor, so

iL(0+)=iL(0)=20mA

but I'm not sure what will happen with the rest of the circuit. Is there a simple way to get i(t)?
Sorry about quality of the picture.

• Is there a simple way to get i(t)? Yes, actually :) Kirchoff's Laws. Since you mentioned, I'm not sure what will happen with the rest of the circuit, I assume that you might not know Kirchhoff's Laws.
– user103380
Sep 8, 2019 at 20:36
• KingDuken would you mind telling me, if it's so simple? I do not have a problem with applying Kirchhoff's laws, it's more that I do not know what will happen with middle branch of the circuit. Will the currrent through middle resistor be 0 or will it jump? I realize that i(t) is a sum of currents in other branches. Sep 8, 2019 at 20:53
• The schematic shows a current source, but fails to define the polarity of the voltage e(t) across it... Sep 8, 2019 at 21:02
• @Harvastum I would recommend using mesh current loops. Your inductor will act like a short circuit, when you use this method.
– user103380
Sep 8, 2019 at 21:04
• There's an arrow pointed upwards. (the + would be up) Sep 8, 2019 at 21:04