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The task is to find Ic in phasor form. The circuit is in steady sinusoidal state.

I used mesh current analysis and I got to that:

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I have no idea how to keep going from there. Also the answer has been given as Ic = 0,5 - j0,5

Sorry if I don't use the terminology correctly. I can explain if needed.

  • \$\begingroup\$ Differentiation transforms to multiplying by \$j\omega\$, so the current source is \$0.5j\omega I_b=jI_b\$ \$\endgroup\$ – Chu Sep 11 at 13:42
  • \$\begingroup\$ @Chu so this means that the equivelant of differentiation on the time field(if my terminology is correct) is multiplying by jω in the frequency field.( im gonna delete the comment . just to check if i get it right) \$\endgroup\$ – lowspacetop Sep 11 at 14:03
  • \$\begingroup\$ Yes. In Laplace, multiplying a variable by s is differentiation and \$s\rightarrow j\omega\$. Are you sure that 0.5 - j0.5 is correct? \$\endgroup\$ – Chu Sep 11 at 14:31
  • \$\begingroup\$ Thanks a lot sir. Cant upvote anything though.Got my answer \$\endgroup\$ – lowspacetop Sep 11 at 14:33
  • \$\begingroup\$ Upvoting isn't an issue. \$\endgroup\$ – Chu Sep 11 at 16:27

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