# Measuring Current by rectifying or voltage-doubling a Current Transformer

Originally, my plan was to just get the voltage output of a current transformer (obviously with the burden resistor circuit stuff and DC biasing circuit stuff) before ADC'ing it, averaging it’s output per second to get the average current per second. However, I will be using all 6 analog pins in the uC to get 6 outputs from a 60hz current transformer, and the uC only has one ADC, which will make my readings kind of inaccurate. Or is it really inaccurate? Please enlighten me.

I was thinking of rectifying the output of the transformer first and using a capacitor to smooth out the output to get a more stable reading, but since I will be dealing with small voltages, I don’t think that's a viable option. Is there some kind of trick in rectifying small signals with as little drop out as possible?

Also, I was wondering if it is possible to use a voltage doubler circuit to boost the voltage output of this transformer, since the highest voltage that can be attained by this circuit is 2Vp, but is this really 2Vp? Or is there also a voltage drop from the diodes that needs to be taken into consideration?

• Enlightenment comes when you present your proposal as a circuit. – Andy aka Sep 12 at 9:11
• The circuits aren't really that complicated as they can be seen on Google, but I will add it. – thisjt Sep 12 at 9:29
• A voltage doubler needs the input voltage to be higher than the forward voltage of the diodes to work. – JRE Sep 12 at 9:30
• That's the reason why it’s a bad idea to use a rectifier. My question is does anyone have some kind of clever way of rectifying while eliminating the voltage drop that a diode introduces. – thisjt Sep 12 at 9:34
• Have you heard of "precision rectifiers?" That would at least get you a DC representation of your AC current. – JRE Sep 12 at 9:54