Here https://www.maximintegrated.com/en/app-notes/index.mvp/id/725 and here https://www.analog.com/media/en/technical-documentation/data-sheets/ADP3603.pdf
The same calculation for the power dissipation given by the pump capacitor in a switching capacitor voltage regulator is made.
What I don't understand, is how a lossless component becomes a lossy component. It is said that the equivalent resistance is not just something that gives you the same RMS current, but it also models the power loss given by switching the capacitor.
It might be the power lost in the ESR or in the Ron of the switches, I thought at first, but these losses are already took into account by other factors explained in other parts of the documents.
So, what other effect does the factor \$ I_{load}*f*C_{pump} \$ really take into account?