This question is hypothetical - there is no specific project, I just have an obsession with efficiency.

I use a lot of 3.3V modules, and have a bunch of single-cell LiPo batteries (which are amazing), so I'm wondering what would be the best way to combine the two if I were to make a project that would need to maximize battery usage efficiency. As far as I know, there are two options:

  1. Low dropout linear regulator (LDO) - not easy to find one with a dropout of 0.2V at 500 mA loads, but the bigger problem is that linear regulators turn the extra voltage into heat, making them very inefficient.
  2. Use a boost converter to bring that LiPo voltage to 5V, and then use a switching regulator to bring it down to 3.3V. I haven't found any modules on Ebay or Aliexpress that would do it with combined efficiency above 90%, unfortunately. And it appears that the switching regulators are very inefficient at low current draws, typical ones dropping down to 60% at 50 mA and below.

Are there any other ways? Is it possible to achieve an efficiency of at least 95% for such a small voltage difference?

  • \$\begingroup\$ 4.2 - 4.0V has relatively small energy. Accept energy loss if linear. Then linear worst case is 3.3/4 = 83.5% at 4V, increasing to 3,3.3.5 ~= 94% at 3.5V. So mean is say 3.3/3.75 = 88%. An LDO with 0.2v dropout is doable. If desired a MOSFET + comparator will allow essentially any dropout desired (almost :-) ). For 0.2V at 500 mA R=V/I =0.2/0.5 = 0.4 Ohm = a very mediocre FET. ie almost an MOSFET willa give the desired dropout. || Best performance would be a buck converter with synchronous dual MOSFET output switch. Efficiencies over 90% should be achievable for most or all of the range. \$\endgroup\$
    – Russell McMahon
    Sep 17, 2019 at 11:23
  • \$\begingroup\$ Welcome to EE.SE! Keep in mind that questions about optimization (i.e., "What is the best ...?") require a definition about what problem dimensions are to be optimized for your application, such as size, speed, energy consumption, user experience, etc. Since these can't be optimized all at once, you need to have a good idea of which ones are most important to you, and be able to articulate that clearly to us. \$\endgroup\$
    – Dave Tweed
    Sep 17, 2019 at 16:28

2 Answers 2


I'd consider using a low-drop-out buck regulator that works almost down to the wire. Such as this one: -

enter image description here

When the input voltage drops to 3.3 volts, the switch inside basically remains on hence, it acts as a regulator down all the way to virtually 3.3 volts.

There are probably several examples of this tech from the usual vendors. Note that the efficiency remains pretty much above 90% from currents as low as 1 mA to over 500 mA.


Modern single-inductor buck-boost converters seem to fit your requirements with efficiencies exceeding 90 % at 50 mA and much below.

The one I looked at was TPS63021 from Texas Instruments. According to the datasheet, with power-save mode activated and input voltage of 3,5V, the efficiency should be above 95% with currents ranging from 1mA to 2A. This is found on page 17, figure 10 of the datasheet.

I'm sure there are also buck-converters where you can get similar efficiency.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.