I am very new to electric engineering, so bear with me ;) Before building the circuit IRL, I wanted to try to build a simple 555 timer with a simulator following Ben eater's tutorial on it. Here are the schematics of the circuit...


If you want to see the tinkercad project... Now, even though I seem to have copied the exact same circuit as shown in the video (or at last so I think) - the first seconds of YT video - the 2uf capacitor doesn't seem to discharge trough Pin 7 when I simulate the circuit. What could be the problem here? I am 100% sure I am missing something very obvious but I have tried, and tried and tried to no avail. So I hope you guys could explain this to me :)

Thanks in advance!

  • \$\begingroup\$ Why do you have a wire joining pin-8 to pin-7? \$\endgroup\$ – brhans Sep 24 '19 at 20:21
  • \$\begingroup\$ How do you know the capacitor doesnt discharge? If the LED is not blinking, the cause may be the LED is connected incorrectly (swap its pins) \$\endgroup\$ – Huisman Sep 24 '19 at 20:22
  • 1
    \$\begingroup\$ What you've posted is a wiring diagram for a breadboard whereas we like to work with a schematic which is a diagram showing device symbols and, for integrated circuits such as your 555, the pin numbers and functions. That way we can see the scheme of the circuit. With such a simple circuit someone will be able to help you out. \$\endgroup\$ – Transistor Sep 24 '19 at 20:22
  • \$\begingroup\$ Sorry, without a schematic this wiring diagram is unreadable. Here is an example of a question with a good schematic: electronics.stackexchange.com/questions/413326/… \$\endgroup\$ – MarkU Sep 24 '19 at 20:22
  • \$\begingroup\$ Like @brhans suggests, it looks like pin 7 & 8 are connected together, but zooming in, the resistor is not stuck into the breadboard. Please improve the image so it becomes clear whether those pins are connected or not. \$\endgroup\$ – Huisman Sep 24 '19 at 20:24

It looks like you have your LED pins shorted together. The way a breadboard works is every pin in that line is connected. You need to put the long LED leg in the line with the wire to pin 3 and the short leg on a new line with the resistor to ground

| improve this answer | |
  • \$\begingroup\$ I am sooo dumb! Thank you sooo much! You're a life saver \$\endgroup\$ – FireGreeks Sep 24 '19 at 20:34

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.