Context: Consider a circuit with only two linear time invariant capacitors. If I charge one the capacitors and then throw a switch that closes the circuit, there will be some redistribution of charge. The capacitors are ideal and there is no resistance in the circuit.


I calculated the energy before the circuit was closed and after the circuit attained a steady state. There was some energy dissipation.

My question is: In what form is the dissipated energy leaving the circuit?

  • \$\begingroup\$ I had a look at the question and the answers however i did not find an answer to my question, which was pertaining to the form in which energy was released by the circuit under ideal conditions (I believe i did mention there are no resistances) \$\endgroup\$ Sep 26 '19 at 2:33
  • \$\begingroup\$ This answer doesn't satisfy you? \$\endgroup\$
    – brhans
    Sep 26 '19 at 3:00
  • \$\begingroup\$ profuse apologies for not doing my homework before asking a question here... @brhans the answer did satisfy me, i overlooked the second answer to that question \$\endgroup\$ Sep 26 '19 at 3:38
  • \$\begingroup\$ The infinite current in the zero ohm resistances tends to account for the losses :-) . | Congratulations on apologising due to an oversight - it's rare. (+1 :-) ). \$\endgroup\$
    – Russell McMahon
    Sep 26 '19 at 11:54