# Non-inverting op-amp saturating incorrectly

## Background

Hello, I'm trying to amplify an audio signal using an LM324N in a non-inverting configuration. I'm not trying to build an audio amplifier to drive speakers, I just need to amplify it a bit for another project.

The problem is when the opamp is on a signal supply (12V to GND) and the input signal goes below 0V the opamp saturates positively (Figure 1) when I expect it to saturate negatively. However when I use a bipolar supply (12V to -12V) it works as anticipated. In my application I would only be able to use the signal supply. I checked the datasheet and the minimum input CMRR is 0V so isn't that an indication that it should be able to swing all the way to the negative rail? I'm not sure what's the issue with the single supply vs the bipolar supply and saturation.

## Question

How can I fix this circuit to work on a single supply (Figure 1) and saturate negatively when the input signal goes negative?

Figure 1 Figure 2

EDIT 1: Added biasing and AC coupling on input and output(figure 3)

Figure 3

EDIT 2: Connected R4 to Vcc/2 (Figure 4)

Figure 4

EDIT 3: Changed AC coupling caps to 100uF

Figure 5

• Comments are not for extended discussion; this conversation has been moved to chat. Oct 2 '19 at 9:26
• Your question has driven me crazy. I tried 2 hours, but couldn't find the proper logic. The internal construction is represented by current sources in the datasheet, which has made it more complicated to analyze. Mar 24 '20 at 19:06
• @SadatRafi check the chat in the comment above yours, they solved the issue as you can see in my last screenshot but I forgot to post an answer Mar 24 '20 at 19:15

Figures 4 and 5 do all of these things right but now the output biasing is not needed (in fact, it just draws unnecessary current from the Amp). A fitting value for the amplification is obtained by choosing middle ground between R2 being 1k and 60k. And the impedance of the caps at your frequency should be a good deal lower than that of the biasing resistors, basically $1 / (2 \pi f C) < 5k$.