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I have the following setup:

  • rougly 15m of WS2812-LED strips divided into two segments
  • Both segments are connected with Data and GND.
  • On one side the LEDs (LEFT SIDE) are also attached to an arduino
  • The Arduino as well as both LED Strip Segments are powered from individual power sources.

Now: - If I power the Left Side (the one with the Arduino) with power banks: no problem.
- If I power all sides with a wall plug USB charger: No problem

If I, however, try to power the right side with a powerbank: it won't work. I originally assumed that this is due to the Strips not drawing enough power but a) they are (as they are all set to full brightness with the Arduino) and b) if so, this would also happen with the left side.

All connections have been checked multiple times and i'm out of ideas how to debug this.

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    \$\begingroup\$ Have you verified that each side draws the same power when on? \$\endgroup\$ – piojo Oct 3 at 8:37
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    \$\begingroup\$ Have you checked that everything you're plugging in isn't exceeding the current limit from the power bank? \$\endgroup\$ – Simon B Oct 3 at 11:57
  • \$\begingroup\$ i toned down the brightness to 10%. at that rate it shouldn't be a problem with power consumption. unfortunately it is. \$\endgroup\$ – Julian Finn Oct 3 at 16:16
  • \$\begingroup\$ @piojo what do you mean the same power? the number of LEDs is slightly different. but as i pointed out, the brightness is at 10% so power consumption isn't the issue \$\endgroup\$ – Julian Finn Oct 3 at 16:17
  • \$\begingroup\$ I meant one side might draw more current. How did you tone down the brightness? Usually brightness is set by PWM, which will not diminish the maximum current draw. Rather the current will be pulsed on and off. My working theory is that your right side needs more current than the left and your power source can't supply it. Of course it could be anything, but that's the obvious solution that you haven't tested yet. Measure it at 100% brightness because your (multimeter doesn't know about PWM). Don't blow the meter: start by measuring current via voltage drop across a small resistance. \$\endgroup\$ – piojo Oct 4 at 2:09

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