0
\$\begingroup\$

I have made project " DTMF Based Land Rover ". The whole circuit is working in usual manner. The voltage at arduino output pins is 3.46 volts. And pin no 16 and 8 are Vcc of L293d respectively So they are connected to 6V. When arduino output is driven into motor drive ic L293d, motors connected at output of ic is not rotating. So can anyone tell me why the motor is not rotating. ( According to me it can be because of low voltage at input pins of L293d. So can anyone suggest how can i increase the voltage at input pins ) If this is due to some different reason, kindly please help me with solution.

\$\endgroup\$
  • 2
    \$\begingroup\$ sorry, neither the Circuit "name" nor "working in usual manner" tell us anything – without a detailed schematic, we can't help you. \$\endgroup\$ – Marcus Müller Oct 15 '19 at 22:10
  • 1
    \$\begingroup\$ And tell us what motors you're using. You are aware that the L293 can only drive its pins to within 1.2V and 1.8V of the rails, so you're basically powering your motor with 3V, not 6. \$\endgroup\$ – TimWescott Oct 16 '19 at 1:05
  • \$\begingroup\$ As many existing questions here will indicate, the L293 and L298 are horrible, extremely lossy chips. They are not suited to low voltage operation at all. \$\endgroup\$ – Chris Stratton Oct 16 '19 at 1:58
  • 1
    \$\begingroup\$ Possible duplicate of L293, L298 and SN754410 H-bridge drivers on low voltage power supply \$\endgroup\$ – Chris Stratton Oct 16 '19 at 3:35
0
\$\begingroup\$

Make sure that you set the enable pins (pins 1 and 9 on the IC) to the correct logic levels to enable the PWM output for the direction you want to turn in.

The datasheet has a lot of information on how to properly use this IC (http://www.ti.com/lit/ds/symlink/l293.pdf)

It sounds like you might be working on a project as a beginner, so here's an instructable that I found online that you can use for reference: https://www.instructables.com/id/L293D-Motor-Driver/

\$\endgroup\$
  • \$\begingroup\$ The fundamental issue is that the asker has chosen the wrong bridge chip for the task. An FET bridge is required, at these voltages a Darlington bridge would at best barely work. \$\endgroup\$ – Chris Stratton Oct 16 '19 at 1:59

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.