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I am not an expert in this area and therefore need suggestion regarding what is the best way out for this case.

For my experiment, I am installing a camera that requires a BNC based trigger signal. In the manual, it suggests the properties as given in the picture:

enter image description here

From what I have known so far, there are usually 50 or 75 ohms BNC connectors and cables. Where can I find 1 kOhms available?

Second, what exactly LVTTL means? Previously, I was using 1.7 V rising edge required trigger signal.

Any help would be appreciated. Thanks!

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For my experiment, I am installing a camera that requires a BNC based trigger signal. In the manual, it suggests the properties as given in the picture

The properties suggested in the manual are the properties of the BNC input port i.e. the port accepts an (LV) TTL signal with a rise time greater than 1 volt per millisecond and presents an impedance to the trigger signal of typically 1 kohm.

LV = low voltage. Various TTL signal level standards: -

enter image description here

Picture source

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LVTTL is low voltage TTL (and TTL is transistor-transistor logic). LVTTL runs at 3.3V instead of the usual 5V. The "5V tolerant" means it doesn't mind being fed conventional 5V TTL if needed.

You won't find a 1kΩ BNC plug. Don't worry about it. It's just an "arm" signal, so impedance matching won't be critical.

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  • \$\begingroup\$ Thank you very much. I don't have much idea about what an "arm" signal really is. In the camera manual it states that it is used to get the camera ready. That's all I know about it so far. \$\endgroup\$ – Tanmay Agrawal Oct 17 at 22:55

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