# Calculating the voltage at Node A

I need to calculate the voltage at node A at the below circuit. Please tell me whether my approach is right

So, I am assuming that the 1000ohms in series with the voltage sources as internal resistances.

Current through the 500ohm would be, I = 10/500 = 20mA

But we need to consider the internal resistance of 1000ohms right So, terminal voltage, Er = V - IR, Er = 10 - (20mA)*(1000Ohms) = 10-20 = -10V ?

What am i doing wrong here?

Please let me know

• If you redraw the circuit with the two 1k resistors on the right in series with the 0.5k resistor you can easily see the voltage divider described by Tabin1000, and the solution is trivial. – jerry Nov 2 '19 at 6:52
• By symmetry, the same value of current flows through each 1k resistor. Let this current be $I$. Then solve using KVL, for example, on one of the meshes. – Chu Nov 2 '19 at 8:14