1
\$\begingroup\$

Suppose you have to amplify a signal with a gain of 2 . The signal is referenced to ground, which means V1 is zero. Is there any reason why one would use this circuit below instead of a normal non-inverting amplifier. https://www.electronicshub.org/differential-amplifier/ Picture obtained from https://www.electronicshub.org/differential-amplifier/

So in that case what is the difference between this circuit and the "normal" non-inverting amplifier were R2=zero and R4= removed. The only difference I see, is that with the differential amplifier you are able to achieve a gain less than 1. Are there any more reasons?accuracy?etc

\$\endgroup\$
  • \$\begingroup\$ No - I don`t think that there are any other reasons for using such a voltage divider... \$\endgroup\$ – LvW Nov 4 '19 at 11:01
  • 1
    \$\begingroup\$ The differential input is useful if the ground of the source and the amplifier are not identical - it can reject ground noise and avoid causing a ground loop. \$\endgroup\$ – Kevin White Nov 4 '19 at 15:27
2
\$\begingroup\$

The beauty of that 4-resistor circuit is the flexibility of centering Vout to whatever you wish, done by unGrounding that R4 and biasing to your desired Vout_center.

| improve this answer | |
\$\endgroup\$
  • \$\begingroup\$ Ohh yes...this may make sense for single supply systems. \$\endgroup\$ – LvW Nov 4 '19 at 14:04

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.