2
\$\begingroup\$

What is the relationship between input phase and output phase of a pll(phase locked loop)?

Why is it called phase locked? Does it keeps/locks output phase to phase of input meaning output has same phase as input?

\$\endgroup\$
  • 4
    \$\begingroup\$ This reads like a homework question. What have you tried so far? \$\endgroup\$ – BB ON Nov 4 '19 at 18:13
  • 3
    \$\begingroup\$ Otherwise: what did a search on internet reveal? \$\endgroup\$ – Huisman Nov 4 '19 at 18:13
  • \$\begingroup\$ No it is not home work question. Please believe me \$\endgroup\$ – Man Nov 4 '19 at 18:18
  • 2
    \$\begingroup\$ As much as we would like to say we have god-like insight into everything, we can't verify whether homework questions are indeed homework. Which is why the necessary condition is that they sound like one, not that they are one. \$\endgroup\$ – BB ON Nov 4 '19 at 18:35
4
\$\begingroup\$

"Phase locked" means that the fundamental feedback mechanism is comparing the phase of the output with the phase of the reference signal, maintaining a constant relationship between them.

The phase offset is not necessarily zero — it depends on the design of the phase detector. Some enforce an offset of 90° or 180°.

| improve this answer | |
\$\endgroup\$
  • \$\begingroup\$ How it maintains a constant relationship between phase of output and phase of refrence?by using any controller? \$\endgroup\$ – Man Nov 5 '19 at 7:37
  • \$\begingroup\$ What do you mean by constant relationship? Does you mean that it tries to keep phase of output same as input refrence ? Or you mean something else by constant relationship? \$\endgroup\$ – Man Nov 5 '19 at 7:39
  • 1
    \$\begingroup\$ maybe more accurate would be to say "constant difference", i.e. the difference of phases is constant (this constant might be 0° but not neccessarily) \$\endgroup\$ – Curd Nov 5 '19 at 10:49
1
\$\begingroup\$

Following up on Dave Tweed answer, the PLL will have leakage currents, thus the UP and the Down pulses will be imbalanced to correct for the leakages.

Leakage currents, such as base-currents into NPN bipolar integrators to compare the UP with Down pulses, will cause large Reference Frequency spurs.

When I diagnosed this, I changed to a Darlington integrator.

| improve this answer | |
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.