0
\$\begingroup\$

I was examining the specs of a breakout board.

It says in there that,

Integrate 10 dof sensors

Adxl345 accelerometer

ITG3200 gyro

HMC5883L Compass

BMP280 pressure sensor

Why is it called as a 10 DOF sensor? In past I was dealing with some IMUs consisting of an accelerometer + a gyroscope and they were called as 6 DOF sensors. Which was a little bit more understandable, I was thinking that 3 measurements from accel and 3 from gyro = 6 degrees of freedom. However in the above case, I am not sure.

\$\endgroup\$
1
  • 1
    \$\begingroup\$ 3-axis gyro + 3-axis accelerometer + 3-axis compass + 1 pressure = 10. \$\endgroup\$
    – Eugene Sh.
    Commented Nov 19, 2019 at 21:34

1 Answer 1

3
\$\begingroup\$

In this context, DOF (degrees of freedom) just mean the number of independent parameters.

Here it is 10:

accelerometer = 3 (acceleration in three dimensions)
gyro = 3 (rate of rotation around three axes)
compass = 3 (magnetic field in three dimensions)
pressure = 1 (well... pressure)
\$\endgroup\$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.