I've been struggling to find the equations needed to find \$V_o\$ and \$I_o\$ for the circuit given below. I came up with the following equations using nodal analysis and wanted to ask whether they were correct or not:
$$V_1: -2A \angle 0º + \frac{V_1}{-j} + \frac{V_1-V_o}{1} + I_o = 0$$
$$V_o: -\frac{V_o-6\angle-90º}{1} + \frac{V_o}{1+j} + \frac{V_o-V_1}{1} - I_o = 0$$
$$V_1 + 12\angle0º = V_o$$
Any help is appreciated!
EDIT: After solving the system of linear equations I got the following results:
$$V_o = -16-20j$$ $$V_1 = -4-20j$$ $$I_o = -30+4j$$
Don't know whether these values are realistic or not