My intention is to calculate the output voltage at the resistance RL when the center tap is removed.
Secondary output voltage will be the sine wave with peak voltage = 1.414 * 12V = 16.968 V. At the positive voltage diode D3 will conduct and negative cycle D2 will conduct. So each output would be equivalent of half-wave rectifier.
Output (VRL(DC)) voltage (DVM reading) would be = 16.968 V - 0.7 V = 16.268 V
( Note: The reason I am taking the peak voltage as the output voltage is due to the high output capacitance (470 µF). That is why I am not using the average voltage equation Vp/π)
Can you please review the output voltage calculation when the center-tap is removed?