The ratings of any relay are mutually independent maximum values, and are not a combination or a best effort recommendation.
Thus, each specific rating must be met. In fact, for certain types of loads, the recommended actual loads are significantly lower than the rated value.
For instance, when driving an incandescent lamp as a load, the filament's initial resistance when cold can be as little as 15% of the resistance when hot. This means, without a resistor in series, said lamp would draw nearly 8 times it's rated current at start-up. Experts will thus often suggest using a relay rated at 8 times the current that the incandescent lamp is nominally supposed to carry.
Similarly, for inductive loads, the voltage spike at circuit break can be several times as much as the operating voltage. The solution in such cases is to use a reverse biased diode across the relay contacts, to shunt the voltage spike harmlessly past the relay contacts.
The contact wattage too is an independent maximum rating, regardless of the values of the other parameters. This is because the rating is computed against the actual resistance of the contacts and their prongs, however small this resistance might be. Exceeding this rating can cause overheating of the relay, insulation meltdown of the driving coil, contacts latching closed, and potentially fire.
Another important point to keep in mind for any electrical equipment is that exceeding any single rating inherently violates Underwriters Laboratories (UL) certification, which means the site of such an installation, be it domestic, commercial or industrial, is no longer covered by insurance. Even an unrelated mishap would thus be denied insurance recourse. Similar rules apply in many countries.
Specific to the two devices mentioned in the question: One of them has a 200 watt contact rating, and the second is even lower at 50 watts. Thus, the requirement far exceeds this rating in both cases.
In sum: No, you can not use those relays for the purpose described.