# Reverse Polarity Protection relay calculation

i want to make reverse polarity protection without voltage drop ,i was searching and i found this

https://www.edn.com/design/analog/4368527/Simple-reverse-polarity-protection-circuit-has-no-voltage-drop

now , i want to size this relay .

load ( 30 A , 48 V ) 1440 Watt

Does load ( normally closed ) matters with relay?

Where load is normally closed so relay is not operated when power supply is connected correctly.

so if that right then

Does relay ( 12 V , 5 A ) 60 Watt can do the work ?

if all above right , then the load will taken into concern is when relay energized so the led ( in photo above ) and resistor here will be loads .

Thanks you .

• Probably about the most ineffective reverse polarity protection in the entire world. What voltage does the relay need to operate? Say 9 volts - this means it won't protect until the reverse voltage is greater than 9 volts. Dec 10, 2019 at 13:41
• @Andyaka thanks for your reply , yea you are right , here i have constant but remote power supply so it can be connected reverse but the value is 48 voltage , so it cant be less than 9 volts , actually i think it will be good if it doesnt drop any volts . Dec 10, 2019 at 13:44
• @Ahmedelmenshawie So wait, you're supplying a 12V relay with 48V? That's not going to protect from reverse voltage at all, reverse voltage will just first destroy the relay and then destroy whatever it was supposed to be protecting. Dec 10, 2019 at 13:48
• @Hearth oh surely you are right , i was totally mistaken here , so if relay is 48 volt same as input here , then how about the load current if its more than the relay can endure Dec 10, 2019 at 13:50
• If the relay is 48 volts then it might not reverse protect until maybe -36 volts. Same as before, it's plain bad. Dec 10, 2019 at 13:52