I have the following problem.

"An amplifier stage with $$\A_{voc}=100\frac{V}{V}\$$, $$\R_i=100k\Omega\$$, $$\R_o=10k\Omega\$$ is connected to another amplifier with $$\A_{voc}=10\frac{V}{V}\$$, $$\R_i=10k\Omega\$$, $$\R_o=100\Omega\$$. They are in cascade, so to speak.

What is the open-circuit voltage gain for this cascade?"

My initial thought was that you just multiplied the two $$\A_{voc}\$$'s together and there you had it.

That would make the total oc-voltage-gain 1000.

But it turns out the answer to this question is $$\500 \frac{V}{V}\$$. Can anyone explain why this is?

There were no schematic included for this problem, but I would assume it looks something like this.

• Where are the resistors placed in the circuit? Where is the circuit of the amplifier stage with the resistors? – Andy aka Dec 12 '19 at 11:34
• I have added a schematic. – Carl Dec 12 '19 at 11:42

I think the question intends that the output of the amplifier with $$\R_O = 10\,\text{k}\Omega\$$ is connected to the input of the amplifier with $$\R_i = 10\,\text{k}\Omega\$$. And that's a big hint right there...
• If I understand you correctly, you are suggesting that $R_o$ and $R_i$ in both amplifiers switch places? If so, I am not sure how to continue from there either... – Carl Dec 12 '19 at 13:35