Simple Square Wave Amplification Technique?

Question

I have a square wave that is 5v peak-to-peak. I need a circuit that can amplify this square wave up to any given supply voltage between 9 and 50v. I don't need much current, nothing more than 100ma certainly, 20-50ma would work. My preference is to use components as cheap as I can get. How can I amplify this square wave for minimal component cost? Is there a way to achieve a square wave with a high peak-to peak voltage without in input pwm?

Edit:

The 0-Vsupply square wave will be fed into the following circuit:

^{simulate this circuit – Schematic created using CircuitLab}

Vout will always float 10v above the supply, minus a few diode drops. The part I am stuck on is how to get a square wave at the supply voltage.

Answer 1

If you don't mind burning up power, but want simple. You need to size your resistors to match whatever you choose for C1 (so if C1 = 1uF, choose R = 100 ohms, which means that Q1 needs to be a power transistor, not a cheezy little 3904).

^{simulate this circuit – Schematic created using CircuitLab}

If you want to be more efficient, but can stand more drop (the output will pull down to about 0.9V, and up to 50V - 0.7V).

^{simulate this circuit}

Answer 2

I found a simple circuit that works for me. Just tested on my oscilloscope. I had originally overlooked this one because power dissipation goes up with supply voltage, but in my application a very small on-time duty cycle will suffice. This will decrease the average power dissipation through the collector resistor to within an acceptable range.

Schematic by Herbert Weidner