- When any amplifier stages are connected the impedance ratio Rin/(Rin+Rout) between these stages determines the attenuation.
- choices for Rout, Rin affect the overall gain or loss
-in current sources, like BJT Common Emitter the collector R is the output impedance and that determines both its gain and output impedance.
- in voltage sources, we must be aware of their output current limits, thermal limits and thus choose a more suitable load.
- in active devices we can tradeoff voltage gain with output impedance using negative feedback.
Other info
All sources have resistance even the grid. Voltage sources are practically defined by zero Ohms voltage source symbol and a series resistance, Rs.
This is also true for passive switches, inductors , L+ DCR , capacitors, C+ ESR and is normally measured at Dc for inductors and some std. f for capacitors.
This is also true for batteries Vbat, ESR which are actually like true voltage sources with a massive supercaps, >10kF, in series for charging up the voltage about 10%.
The same is true for current sources defined by high impedance controlled current and some parallel load resistance like common emitter transistors with Rc.
The same is true for Op Amps which can reduce the output error with negative feedback and thus reduce the output impedance of the internal series resistor by the same amount until the current limit is reached.
In general this load reduction of voltage is commonly specified in voltage regulators as Load Regulation Error (%) which is always due to the impedance ratio of the load to the Load + source (%).
In RF amplifiers low impedance is often necessary and both voltage and current are important so we always deal in power (Watts). Also since maximum power is often important between stages, the impedance must be matched. This is true for 50 Ohm system but it also means the load loss is 50% in power but that is still the max. power transfer condition.
Paradox
We would not want this load regulation error for a DC power supply so they are often specified <= 2% and thus by V/Imax * % error we can estimate the source impedance. Yet for a PV Solar Array where power = P= V*I if we load it down we must know its current source impedance R=Voc/Isc and always load with the same impedance, R in order to obtain this power which often occurs at <82% Voc.
Simple solutions
For voltage amplifiers we need more current and a lower output impedance.
For active switches like FETs we need lower RdsOn and for Bipolar Junction transistors (BJT) , we need lower Rce = Vce/Ic when saturated.
p.s. Season's greeting from Toronto