So I've been trying to understand how an RC lowpass filter works, and I think I got it, but I just need some clarification.
My understanding: So an RC Lowpass filter in a nutshell is just a voltage divider made to filter out higher frequency signals. The cutoff frequency is dependent on the R and C values of the filter.
The equation for the impedance of a capacitor is 1/jwC. So with low frequency signals (i.e. 20 Hz), the impedance of the capacitor will be high. Now looking at our voltage divider, since we have a large impedance connected to ground, Vout should be close to Vin.
Now let say we have a high frequency signal (i.e. 1GHz). Here, the impedance of the capacitor will be low. And because of that, Vout will instead be a small value, close to 0V.
Can anyone clarify if my thought process is right?
low signalsmean? ... low voltage? ... low current? ... what does
high signalmean? ... please edit your question with correct terms \$\endgroup\$